### Percentage Basic Concepts:

- Percentage means per 100 or for every 100. i.e. X % of Y = (X/Y)*100

- Let the population of a town be P now and suppose it increases at the rate of R% per annum, then:

^{n }

Population 'n' years ago = P

**/**[1 + (R/100)]

^{n }

- If the price of the commodity increases by R %, then the reduction in consumption so as not to increase the expenditure is: {[R/(100 + R)] * 100}%
- If the price of the commodity decreases by R %, then the increase in consumption so as not to decrease the expenditure is: {[R/(100 - R)] * 100}%
- Let the present value of a machine be P. Suppose it depreciates at the rate of R% per annum.

^{n}

Value of the machine n years ago = P

**/**[1 - (R/100)]

^{n}

Problems on Percentages:

1. Find 20 % of 6200 ?

A) 1200 B) 1220 C) 1240 D) 1250

2. 40 is what percentage of 20 ?

A) 50 B) 150 C)200 D)250

3. 12 % of a certain sum of money is Rs. 43.5. Find the sum ?

A) Rs. 362.5 B) 364.5 C) 365.0 D) 366.5

4. 16 % of 40 % of a value is 8. Then find the value ?

A) 75 B) 100 C) 125 D) 150

5. The population of a town has increased from 60,000 to 65,000. Find the increase percent ?

A) 22/3 B) 25/3 C) 50/7 D) 52/7

6. In an election of two candidates, the candidate who gets 41 % is rejected by a majority of 2412 votes. Find the total no. of votes polled ?

A) 13,100 B) 13,200 C) 13,300 D) 13,400

7. If the income of Rajesh is more than Suresh by 25 %. Then how much percent of Suresh income is less than that of Rajesh ?

A) 5 % B) 10 % C) 15 % D) 20 %

8. Prakash scored 60 % marks in an exam and Raghu scored 62 % of marks. If one of them has got 5 marks more than other. Find maximum marks ?

A) 150 B) 200 C) 250 D) 300

9. An ore contain 15 % of iron. How many kg of the ore are required to get 72 kg of iron ?

A) 480 B) 460 C) 380 D) 490

10. If the length of a rectangle is increased by 30 % and its breadth is decreased by 20 %. Then what is effected of its area ?

A) 2 % Increase B) 4 % Increase

C) 2 % Decrease D) 4 % Decrease

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